]> $$\frac{1}{\left(\omega \pi \right)}{e}^{-}\frac{{\left(x-\xi \right)}^2}{\left(2{\omega }^2\right)}{\int }_{-\infty }^{\left(\alpha \left(\frac{\left(x-\xi \right)}{\omega }\right)\right)}{e}^{-}\frac{t^2}{2}dt$$